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Lesson 3 of 3

Adding sines.

About 20 minutes · 6 practice questions

Every repeating wave is a sum of sines: circles spinning on circles, the square wave’s odd sines and their sizes, the triangle wave that converges fast, and the bump beside a jump that never goes away.

Step 1 of 6 · One circle

Step 1 of 6

One circle

In the trigonometry Unit you saw a point turning on a circle draw a sine wave. In complex numbers: beiktb e^{ikt}⁠ is a point turning kk⁠ times as fast, on a circle of radius bb⁠, and its height is bsin⁡ktb\sin kt⁠. Add several of these, each circle on the rim of the last, and the tip of the chain draws a sum of sines. Joseph Fourier claimed that every repeating wave can be built this way:

f(t)=b1sin⁡t+b2sin⁡2t+b3sin⁡3t+…f(t) = b_1 \sin t + b_2 \sin 2t + b_3 \sin 3t + \dots⁠

This is a Fourier series. Here the wave is a square wave, and there is only one circle: the first term of its series, 4πsin⁡t\frac{4}{\pi}\sin t⁠. Work out the circle’s radius.

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Step 2 of 6

More circles

The series of the square wave, ss⁠, has only odd frequencies, and each term shrinks like one over its frequency:

s(t)=4π(sin⁡t+sin⁡3t3+sin⁡5t5+… )s(t) = \frac{4}{\pi}\left(\sin t + \frac{\sin 3t}{3} + \frac{\sin 5t}{5} + \dots\right)⁠

Here there are 44⁠ circles, and Show the sines draws each sine on its own on the graph. Predict what the fifth circle will add.

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Step 3 of 6

The triangle wave

With Wave on the triangle, gg⁠, the terms shrink faster, like one over the square of the frequency:

g(t)=8π2(sin⁡t−sin⁡3t9+sin⁡5t25−… )g(t) = \frac{8}{\pi^2}\left(\sin t - \frac{\sin 3t}{9} + \frac{\sin 5t}{25} - \dots\right)⁠

A smoother wave needs fewer fast sines. Work out the radius of the third circle.

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Step 4 of 6

Beside the jump

The square wave jumps all at once from −1-1⁠ to 11⁠. A sum of smooth sines cannot jump like that, so beside every jump it rises a little above the wave, then wobbles. Show the sines is now at the end, and the board shows the bump’s height. Predict what will happen to it as you add Terms.

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Step 5 of 6

No jump

The bump belongs to jumps, not to the wave itself. Try all three choices of Wave, then answer.

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Step 6 of 6

The highest point

Under Show the sines you see the sum up close beside the jump.

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Still of the Fourier series 3D scene
Interactive scene

Loading the interactive version…

Each step sets up the Scene for you, and a control marked “fixed” stays put for that step.

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Practice · Calculate

Terms is 11⁠: one circle, and the square wave’s first sine, b1sin⁡tb_1 \sin t⁠ with b1=4πb_1 = \frac{4}{\pi}⁠. What is the circle’s radius, b1b_1⁠, as a decimal?

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Practice · Predict, then look

There are 44⁠ circles of the square wave: they spin 11⁠, 33⁠, 55⁠ and 77⁠ times as fast as the first. How many turns will the fifth circle make while the first turns once?

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Practice · Calculate

Wave is the triangle, with 33⁠ terms. Term kk⁠ has size 8π2k2\frac{8}{\pi^2 k^2}⁠, with kk⁠ odd only. What is the radius of the third circle?

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Practice · Predict, then look

Beside each jump of the square wave the sum rises above the wave, by about 9%9\%⁠ of the jump, with 55⁠ terms. What will happen to this bump as you add terms, up to 1515⁠?

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Practice · Choose

Try all three Wave shapes with 1515⁠ terms, and drag Show the sines all the way. In which wave does the sum not rise above the wave?

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Practice · Calculate

Wave: Square, and Terms 1515⁠. The wave jumps from −1-1⁠ to 11⁠, and beside each jump the sum rises above the wave by about 9%9\%⁠ of the size of the jump. What is the highest value the sum reaches?