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Lesson 3 of 3

Foci and Dandelin spheres.

About 25 minutes · 6 practice questions

Why an ellipse has two foci whose distances add up to a constant: Dandelin spheres, the gardener’s ellipse with a string, the link between a, b and c, the parabola with one focus and a directrix, and the hyperbola with a fixed difference.

Step 1 of 6 · The gardener’s ellipse

Step 1 of 6

The gardener’s ellipse

A gardener who wants an oval bed drives in two pegs, ties a slack string to them, and pulls it taut with a stick that marks the line in the soil. The stick runs round an ellipse, and the pegs are its foci: at every point PP⁠ of the ellipse, PF1+PF2PF_1 + PF_2⁠ equals the string’s length.

In 1822 Germinal Pierre Dandelin proved this with the cone. Show the focus spheres shows two balls that fit snugly inside the cone, one above the cut and one below. Each ball touches the cut at one point, a focus, and the cone along a circle. From PP⁠ you can measure to each ball in two ways: to the focus, or along the cone’s side to the circle, and those two tangents are equal. Work out the sum of the distances.

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Step 2 of 6

a, b and c

The semi-major axis aa⁠, the semi-minor axis bb⁠ and the distance to a focus cc⁠ are linked by a right triangle: from the end of the minor axis, the distance to each focus is aa⁠, because the sum is 2a2a⁠ and the two distances are equal. So a2=b2+c2a^2 = b^2 + c^2⁠. Work out bb⁠.

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Step 3 of 6

One focus

As the tilt approaches 60°60^\circ⁠, the ellipse stretches out, and the larger ball is pushed up the cone. Predict what happens to it at the parabola, then increase Tilt of the cut.

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Step 4 of 6

The directrix

Each ball touches the cone along a circle, and that circle’s plane cuts the plane of the cut in a straight line: the directrix. On every conic section, the ratio of a point’s distance to the focus, PFPF⁠, to its distance to the directrix, PDPD⁠, is the eccentricity. The point running along the curve measures both distances. This parabola has one focus and one directrix, and it is also the parabola of the quadratic function y=ax2y = ax^2⁠.

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Step 5 of 6

Hyperbola

On a hyperbola the balls are in the two halves of the cone, one above the tip and one below, and each focus is inside one of the branches. Move Distance from the tip, and watch both balls stay touching the cut.

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Step 6 of 6

Vertex and focus

Back to the first ellipse. The vertices are the two points farthest apart, and the foci sit between them on the same axis.

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Still of the Conic sections 3D scene
Interactive scene

Loading the interactive version…

Each step sets up the Scene for you, and a control marked “fixed” stays put for that step.

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Practice · Calculate

The ellipse is 3.123.12⁠ units long from vertex to vertex, so 2a≈3.122a \approx 3.12⁠. PP⁠ is any point on the ellipse. What is PF1+PF2PF_1 + PF_2⁠, the sum of the distances from PP⁠ to the two foci?

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Practice · Calculate

In the same ellipse a≈1.559a \approx 1.559⁠ and c=0.9c = 0.9⁠. What is bb⁠, the semi-minor axis?

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Practice · Predict, then look

The tilt is 50°50^\circ⁠, and both focus spheres are shown. What will happen to the larger ball when the tilt reaches 60°60^\circ⁠ and the cut is a parabola?

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Practice · Choose

The point running along the parabola shows its distance to the focus, PFPF⁠, and to the directrix, PDPD⁠. The eccentricity is e=PFPD=1e = \frac{PF}{PD} = 1⁠. What is true at every point of the parabola?

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Practice · Choose

The tilt is 80°80^\circ⁠: a hyperbola, with a focus inside each branch. PP⁠ is on one branch. What stays the same along the hyperbola?

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Practice · Calculate

In the ellipse a≈1.559a \approx 1.559⁠, and the distance from the centre to each focus is c=0.9c = 0.9⁠. What is the distance from a vertex to the focus nearest it?