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Lesson 2 of 4

Shifting a parabola.

About 20 minutes · 3 practice questions

How to move y = x² right, left, up and down, and how to read the vertex straight off vertex form.

Step 1 of 4 · Three steps from the basic parabola

Step 1 of 4

Three steps from the basic parabola

You can build any parabola from y=x2y = x^2⁠ in three steps, and each one goes straight into vertex form:

y=a(x−p)2+ky = a(x - p)^2 + k⁠

  1. Stretch by a factor of aa⁠: the parabola gets narrower or wider, and may flip over.
  2. Sideways, a shift of pp⁠: to the right when pp⁠ is positive, to the left when pp⁠ is negative.
  3. Up or down, a shift of kk⁠: up when kk⁠ is positive, down when kk⁠ is negative.

The Scene shows y=2(x−3)2−2y = 2(x-3)^2 - 2⁠, with Look inside at the start. Step through the stages and watch the pink vertex travel from (0,0)(0, 0)⁠ to (3,−2)(3, -2)⁠.

Step 2 of 4

Which way?

The vertical shift is easy to read: +k+k⁠ lifts the graph. The horizontal shift is the confusing one, because it is written inside the brackets with a minus sign. Try Horizontal shift p in the Scene, then answer.

To the question

Step 3 of 4

Hit the ring

There is a ring in the Scene at (2,−3)(2, -3)⁠. a is locked at 11⁠, so only the shifts change the parabola.

To the question

Step 4 of 4

Read the vertex

In vertex form you can read the vertex without any working: it is the point (p,k)(p, k)⁠. Just be careful with the sign inside the brackets: (x+1)2(x+1)^2⁠ is (x−(−1))2(x - (-1))^2⁠.

To the question

Interactive scene

Loading the interactive version…

Each step sets up the Scene for you, and a control marked “fixed” stays put for that step.

To the experiment

Practice · Choose

The graph of y=(x−3)2y = (x-3)^2⁠ is the graph of y=x2y = x^2⁠ after a shift. Which shift?

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Practice · Reach the target

Move the parabola so that its vertex lands on the ring at (2,−3)(2, -3)⁠, then press Check.

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Practice · Choose

What is the vertex of the parabola y=(x+1)2−4y = (x+1)^2 - 4⁠?