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Lesson 1 of 5

Starlight and temperature.

About 25 minutes · 6 practice questions

A glowing body gives out a continuous spectrum that depends only on its temperature. Wien's law links the peak to the temperature, the Stefan–Boltzmann law the power, and together they read a star's temperature from its colour.

Step 1 of 6 · The colour of heat

Step 1 of 6

The colour of heat

You cannot send a thermometer to a star, but you can take its light apart. In the Scene a lump of tungsten sits in an open furnace, glowing red at 950 K. Every warm body gives out electromagnetic waves, and what it gives out depends almost only on its temperature, not on the material: such a body is called a blackbody, because it absorbs all the light that falls on it. Stars are very close to blackbodies.

Change Temperature of the lump and watch the colour change: below about 800 K it does not glow at all, and then it goes red, orange, yellow and white.

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Step 2 of 6

Wien’s law

Show the whole spectrum shows the whole curve, including the part the eye cannot see: how much light the lump gives out at each wavelength. The curve has a peak, and Wien’s displacement law says where:

λmax⁡=bT,b≈2.90×10−3 m⋅K\lambda_{\max} = \frac{b}{T}, \qquad b \approx 2.90 \times 10^{-3}\ \mathrm{m \cdot K}⁠

Here TT⁠ is in kelvin. The peak goes inversely with the temperature: a body twice as hot gives out mostly at half the wavelength. Temperature of the lump is locked at 1300 K.

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Step 3 of 6

Hotter and shorter

Predict what will happen to the curve as the lump heats up, then compare with the reading of the peak.

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Step 4 of 6

One micrometre

Now turn Wien’s law round: if you know where the peak is, you know the temperature. That is how a star’s temperature is measured.

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Step 5 of 6

The fourth power

As the lump heats up, the curve does not only move: it also grows enormously. The area under it is the total power each square metre gives out, and the Stefan–Boltzmann law says how much:

P=σT4,σ≈5.67×10−8 W/(m2⋅K4)P = \sigma T^4, \qquad \sigma \approx 5.67 \times 10^{-8}\ \mathrm{W/(m^2 \cdot K^4)}⁠

The power reading is beside the Scene. A whole star’s power is PP⁠ times its surface area, 4πR24\pi R^2⁠: a star can be bright because it is hot, or because it is huge.

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Step 6 of 6

The Sun’s temperature

The furnace goes only up to 3000 K. Show the whole spectrum now adds, as a dashed line, the Sun’s curve for comparison. Use its peak.

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Still of the Blackbody radiation 3D scene
Interactive scene

Loading the interactive version…

Each step sets up the Scene for you, and a control marked “fixed” stays put for that step.

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Practice · Choose

Orion has a red star, Betelgeuse, and a bluish-white one, Rigel. Which of them is hotter at its surface?

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Practice · Calculate

Temperature of the lump is locked at 1300 K, and it glows orange-red. At what wavelength is the peak of its radiation? b=2.90×10−3 m⋅Kb = 2.90 \times 10^{-3}\ \mathrm{m \cdot K}⁠.

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Practice · Predict, then look

The lump is red hot, at 950 K. It is heated to 1800 K, yellow hot. Which way will the peak of the curve move?

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Practice · Reach the target

Change Temperature of the lump until the peak of its radiation is at exactly 1000 nm, one micrometre, and press Check.

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Practice · Predict, then look

At 1300 K each square metre of the lump gives out about 162 kW. The temperature is doubled to 2600 K. How many times more power will it give out?

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Practice · Calculate

Show the whole spectrum has added the curve of sunlight, and its peak is at about 502 nm, in blue-green light. What is the temperature of the Sun’s surface?