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Lesson 3 of 4

Galvanic cells.

About 30 minutes · 5 practice questions

How a redox reaction makes electricity: anode and cathode, voltage from standard potentials, why the poles can swap, how much voltage is lost inside the cell, and what the salt bridge does.

Step 1 of 5 · A cell’s voltage

Step 1 of 5

A cell’s voltage

When zinc is dipped in a solution of copper ions, the electrons go straight from the zinc to the ions, and the energy turns into heat. A galvanic cell separates the two halves of the reaction, so the electrons have to travel through a wire, where they can be used. The electrode where oxidation happens is the anode, the negative terminal; the one where reduction happens is the cathode, the positive terminal.

How strongly each half-cell “pulls” electrons is measured by its standard reduction potential, E°E^\circ⁠, against a hydrogen electrode, in 1 mol/L solutions at 25 °C. The cell’s voltage with no current flowing, its electromotive force (emf, ε\varepsilon⁠), is the difference:

Ecell∘=Ecathode∘−Eanode∘E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}}⁠

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Step 2 of 5

Choosing the metals

Metal E°E^\circ⁠
Magnesium −2.37 V
Zinc −0.76 V
Iron −0.44 V
Lead −0.13 V
Copper +0.34 V
Silver +0.80 V

The metal in the right half-cell is always copper. Load resistance is fixed at 500 Ω, nearly an open circuit, and Left metal is free.

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Step 3 of 5

The poles swap

Which electrode is the anode is not fixed in advance: it is always the metal with the lower potential of the two. Show ions and electrons is On, and Left metal is now fixed at zinc.

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Step 4 of 5

Voltage under load

Like any source of voltage, the cell has internal resistance: the ions have to travel through the solutions and the salt bridge, and that costs voltage. In the Scene’s cell the internal resistance is 10 Ω. When a current II⁠ flows, the voltage at the terminals is less than the emf: V=ε−IrV = \varepsilon - Ir⁠. Now Load resistance is 20 Ω.

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Step 5 of 5

The salt bridge

In the zinc beaker positive ions are made all the time, and in the copper beaker positive ions are used up. The salt bridge, a tube of salt solution, closes the circuit inside the cell. Show ions and electrons is On: watch what moves through it.

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Still of the Electrochemistry 3D scene
Interactive scene

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Each step sets up the Scene for you, and a control marked “fixed” stays put for that step.

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Practice · Calculate

The standard reduction potentials are E°(Cu2+/Cu)=+0.34 VE^\circ(\mathrm{Cu^{2+}/Cu}) = +0.34\ \mathrm{V}⁠ and E°(Zn2+/Zn)=−0.76 VE^\circ(\mathrm{Zn^{2+}/Zn}) = -0.76\ \mathrm{V}⁠. What is the voltage of a zinc–copper cell with no current flowing?

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Practice · Reach the target

Choose, with Left metal, the metal that gives the cell the highest voltage, then press Check.

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Practice · Predict, then look

In the zinc–copper cell the zinc dissolves. Which strip will dissolve when you change the left metal to Silver?

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Practice · Calculate

The zinc–copper cell, 1.10 V, has an internal resistance of 10 Ω. Load resistance is 20 Ω. What does the meter across the load read?